What is the temperature in Kelvin of 2 liters of water at 30°C after adding 500 calories of heat?

To determine the temperature in Kelvin of the water after adding heat, it's important to first understand the relationship between temperature scales and the specific heat formula.

Initially, the water is at 30°C. To convert this temperature to Kelvin, we use the formula:

[ K = °C + 273.15 ]

So, 30°C converts to:

[ 30 + 273.15 = 303.15 K ]

Next, we focus on the heat added to the water. The specific heat capacity of water is approximately 1 calorie/gram°C. Given that the volume of water is 2 liters (which is equivalent to 2000 grams since the density of water is about 1 g/mL), we can calculate the temperature change resulting from the added heat.

The formula to calculate the change in temperature (( \Delta T )) when heat (( Q )) is added is:

[ Q = m \cdot c \cdot \Delta T ]

Where:

• ( Q ) is the heat added in calories (500 calories),

• ( m ) is the mass of the water in grams (2000 grams),

• ( c ) is the specific heat capacity of water (